2x^2+14x-2352=0

Solution for 2x^2+14x-2352=0 equation:

2x^2+14x-2352=0

a = 2; b = 14; c = -2352;
Δ = b2-4ac
Δ = 142-4·2·(-2352)
Δ = 19012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19012}=\sqrt{196*97}=\sqrt{196}*\sqrt{97}=14\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{97}}{2*2}=\frac{-14-14\sqrt{97}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{97}}{2*2}=\frac{-14+14\sqrt{97}}{4}
$